Python 井字棋

发布时间:2017-09-05 10:32:03
Python 井字棋

# Tic Tac Toe import random def drawBoard(board): # 打印棋盘 # "board"是长度为10的列表,为了方便输入,忽略第一个元素board[0] print('\n\n\n\n') print('\t\t\t┌─┬─┬─┐') print('\t\t\t│'+board[7]+' │'+board[8]+' │'+board[9]+' │') print('\t\t\t├─┼─┼─┤') print('\t\t\t│'+board[4]+' │'+board[5]+' │'+board[6]+' │') print('\t\t\t├─┼─┼─┤') print('\t\t\t│'+board[1]+' │'+board[2]+' │'+board[3]+' │') print('\t\t\t└─┴─┴─┘') def inputPlayerLetter(): # 让玩家选择棋子 # 返回一个列表,第一个是玩家的棋子,第二个是电脑的 letter = '' while not (letter == 'X' or letter == 'O'): print('Do you want to be X or O?') letter = input().upper() if letter == 'X': return ['X', 'O'] else: return ['O', 'X'] def whoGoesFirst(): # 随机产生谁先走 if random.randint(0, 1) == 0: return 'computer' else: return 'player' def playAgain(): # 再玩一次?输入yes或y返回True print('Do you want to play again? (yes or no)') return input().lower().startswith('y') def makeMove(board, letter, move): #落子 board[move] = letter def isWinner(bo, le): # 判断所给的棋子是否获胜 # 参数为棋盘上的棋子(列表)和棋子符号 # 以下是所有可能胜利的情况,共8种 return ((bo[7] == le and bo[8] == le and bo[9] == le) or (bo[4] == le and bo[5] == le and bo[6] == le) or (bo[1] == le and bo[2] == le and bo[3] == le) or (bo[7] == le and bo[4] == le and bo[1] == le) or (bo[8] == le and bo[5] == le and bo[2] == le) or (bo[9] == le and bo[6] == le and bo[3] == le) or (bo[7] == le and bo[5] == le and bo[3] == le) or (bo[9] == le and bo[5] == le and bo[1] == le)) def getBoardCopy(board): # 复制一份棋盘,供电脑落子时使用 dupeBoard = [] for i in board: dupeBoard.append(i) return dupeBoard def isSpaceFree(board, move): # 判断这个位置是否有子,没子返回True return board[move] == ' ' def getPlayerMove(board): # 玩家落子 move = ' ' while move not in '1 2 3 4 5 6 7 8 9'.split() or not isSpaceFree(board, int(move)): print('What is your next move? (1-9)') move = input() return int(move) def chooseRandomMoveFromList(board, movesList): # 随机返回一个可以落子的坐标 # 如果没有所给的movesList中没有可以落子的,返回None possibleMoves = [] for i in movesList: if isSpaceFree(board, i): possibleMoves.append(i) if len(possibleMoves) != 0: return random.choice(possibleMoves) else: return None def getComputerMove(board, computerLetter): # 确定电脑的落子位置 if computerLetter == 'X': playerLetter = 'O' else: playerLetter = 'X' # Tic Tac Toe AI核心算法: # 首先判断电脑方能否通过一次落子直接获得游戏胜利 for i in range(1, 10): copy = getBoardCopy(board) if isSpaceFree(copy, i): makeMove(copy, computerLetter, i) if isWinner(copy, computerLetter): return i # 判断玩家下一次落子能否获得胜利,如果能,给它堵上 for i in range(1, 10): copy = getBoardCopy(board) if isSpaceFree(copy, i): makeMove(copy, playerLetter, i) if isWinner(copy, playerLetter): return i # 如果角上能落子的话,在角上落子 move = chooseRandomMoveFromList(board, [1, 3, 7, 9]) if move != None: return move # 如果能在中心落子的话,在中心落子 if isSpaceFree(board, 5): return 5 # 在边上落子 return chooseRandomMoveFromList(board, [2, 4, 6, 8]) def isBoardFull(board): # 如果棋盘满了,返回True for i in range(1, 10): if isSpaceFree(board, i): return False return True print('Welcome to Tic Tac Toe!') while True: # 更新棋盘 theBoard = [' '] * 10 playerLetter, computerLetter = inputPlayerLetter() turn = whoGoesFirst() print('The ' + turn + ' will go first.') gameIsPlaying = True while gameIsPlaying: if turn == 'player': # 玩家回合 drawBoard(theBoard) move = getPlayerMove(theBoard) makeMove(theBoard, playerLetter, move) if isWinner(theBoard, playerLetter): drawBoard(theBoard) print('Hooray! You have won the game!') gameIsPlaying = False else: if isBoardFull(theBoard): drawBoard(theBoard) print('The game is a tie!') break else: turn = 'computer' else: # 电脑回合 move = getComputerMove(theBoard, computerLetter) makeMove(theBoard, computerLetter, move) if isWinner(theBoard, computerLetter): drawBoard(theBoard) print('The computer has beaten you! You lose.') gameIsPlaying = False else: if isBoardFull(theBoard): drawBoard(theBoard) print('The game is a tie!') break else: turn = 'player' if not playAgain(): break


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